单项选择题
A.logX=(-K/2.303)t+logX0 B.10gC=(-K/2.303)t+logC0 C.logC′=(-K/2.303)t′+log(K0/VK) D.10gC′=(-K/2.303)t′+log[K0(1-e-KT)/VK] E.C=K0(1-e-Kt)/KV
A.C=C<sub>o</sub>e<sup>-Kt</sup> B.X=X<sub>o</sub>e<sup>-Kt</sup> C. D. E.lnC=1nC<sub>o</sub>-Kt