单项选择题

有如下程序：
#include ＜iostream.h＞
#include ＜iomanip.h＞
using namespace std;
class CSum
int x,y;
public:
CSum (int x0,int y0):x(x0),y(y0)
friend ostream & operator＜＜(ostream& os,const CSum& x

A．

&nbs

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单项选择题

有以下程序 #include ＜iostream＞ #include ＜string＞ using namespace std; class base private: char baseName[10]; public: base () strcpy(baseName, Base ); virtual char *myName() return baseName; char *className() return baseName; ; class Derived : public base private: char derivedName[10]; public: Derived() strcpy(derivedName, Derived ); char *myName() return derivedName; char *className() return derivedName; ; void showPtr(base &p) cout＜＜p.myName () ＜＜＜＜p.className (); int main () base bb; Derived dd; showPtr(dd); return 0; 运行后的输出结果为

A．Derived Base
B．Base Base
C．Derived Derived
D．Base Derived

单项选择题

有如下程序： #include ＜iostream.h＞ using namespace std; class Base public: Base() cout＜＜ BB ; f(); voidf()cout ＜＜ Bf ; ; class Derived: public Base public: Derived ()cout＜＜ DD ; void f()cout＜＜ Df ; ; int main()Derived d; return 0; 执行上面的程序将输出

A．BBBfDD
B．BBDfDDDf
C．DD
D．DDBBBf

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