单项选择题
A.operator-( B.operator-(y, C.operator-( D.operator-(x,
A.void f1(double&{--x;) B.double f2(double {return x-1.5;) C.void f3(double {--x;) D.double f4(double *{--*x;retum *x;}
A.long *p=new long; B.long p; C.long *p=new long(; D.longpr[10];