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将1．015 1修约至十分位的0．2个单位，修约数为( )。A.1．00B.1．01C.1．02

A.015
B.2个单位，修约数为(
C.1．00
B.1．01
C.1．02
D.1．015

【参考答案】

C
本题考查数值修约规则。修约规则要求如果为修约间隔整数倍的一系列数中，只有一个数最接近拟修约数，则该数就是修约......

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回归分析就是确定变量与变量之间的关系，大致分为两类，是( )A.确定性B.非确定性

A.确定性
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A.As
B.
As
C.
Still,
D.A
E.
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