问答题

简述碳的质量分数为0.4%和1.2%的铁碳合金从液态冷至室温时的结晶过程。

【参考答案】

\n \n \n 对于WC=1.2%的铁碳合金，当其从液态冷至室温过程中，会相继发生如下过程：①L→A，液态逐渐减少，A逐渐增多；②部分A→Fe3CII，形成A+Fe3CII组织；③剩余A→P；④室温时最终形成F+Fe3CII组织。\n \n \n

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