未分类题
设函数u=u(x,y)的全微分du=[ex+f'(x)]ydx+f'(x)dy，其 中f在(-∞，+∞)内具有二阶连续的导数，且f(0)=4，f'(0)=3，求f(x)及u(x,y)
【参考答案】
f(x)=2(1+ex)+xex
热门
试题
未分类题
设方程F(x2+y2，y2+z2，z2+x2)=0确定了函数z=z(x，y)，其中F有连续一阶偏导数，求 style='FONT-SIZE: 16px; FONT-FAMILY: zuoyeFont_mathFont, Microsoft Yahei, 宋体, sans-serif; WHITE-SPACE: normal; TEXT-TRANSFORM: none; WORD-SPACING: 0px; FLOAT: none; FONT-WEIGHT: normal; COLOR: rgb(51,51,51); FONT-STYLE: normal; ORPHANS: 2; WIDOWS: 2; DISPLAY: inline !important; LETTER-SPACING: normal; BACKGROUND-COLOR: rgb(255,255,255); TEXT-INDENT: 0px; font-variant-ligatures: normal; font-variant-caps: normal; -webkit-text-stroke-width: 0px'>函数z = z( x,y)在点(1,0,-1)处的全微分dz, style='FONT-SIZE: 16px; FONT-FAMILY: zuoyeFont_mathFont, Microsoft Yahei, 宋体, sans-serif; WHITE-SPACE: normal; TEXT-TRANSFORM: none; WORD-SPACING: 0px; FLOAT: none; FONT-WEIGHT: normal; COLOR: rgb(51,51,51); FONT-STYLE: normal; ORPHANS: 2; WIDOWS: 2; DISPLAY: inline !important; LETTER-SPACING: normal; BACKGROUND-COLOR: rgb(255,255,255); TEXT-INDENT: 0px; font-variant-ligatures: normal; font-variant-caps: normal; -webkit-text-stroke-width: 0px'>是xyz + （x2 + y2 + z2）^(1 2) =2^(1 2)