未分类题

取水样Vs=100mL,测量总硬度,滴定管初读数为V1=1.05mL,终读数为V2=30.5mL,EDTA标准液浓度为c=0.001mol/L(1/2EDTA),问该水样的硬度为多少?

【参考答案】

Ho=(1000cV)/Vs其中V=V2-V1
=[1000×0.001×(30.5-1.05)]/100......

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